00:01
We have to find the 7a resistance here.
00:05
So, rth equals 4 times 6 over 4 plus 6, which is equals to 2 .41.
00:16
So, according to maximum power transfer theorem, maximum power will be transferred to the load when rth, that means r load, is equals to 2 .40.
00:41
So, for the b part, applying this theorem at node 2, we have v2 minus v1 over 12 plus v2 minus vth over 15 plus 18 equals 0.
01:02
We wrote vts in place of v3 because v3 is equals to th.
01:11
So, we have v2 1 over 12 plus 1 over 15 minus v1 over 12 minus vth over 15 equals minus 18, which is equation number 1.
01:34
Now, node 1 and 3 form super nodes.
01:37
So, applying kcl to super node, we have v1 over 4 minus 12 plus v1 minus v2 over 2 plus v3 over 6 plus v3 minus v2 over 15 is equals to 0.
02:03
So, we have v1 1 over 4 plus 1 over 12 minus v2 1 over 2 plus 1 over 15 plus vth 1 over 16 plus 1 over 15 equals 12.
02:33
And this is our equation 2.
02:39
But, we want v3 equals 36.
02:46
Or, we can write it as v1 minus vth equals 36.
02:52
So, we have v1 2 over 36 plus vth.
03:01
Substituting v1 in equation 1, we have v2 1 over 12 plus 1 over 15 plus vth 1 over 12 plus 1 over 15 equals minus 15...