Question

Find to 4 decimal places the following binomial probabilities using the normal approximation. a. n = 140, p = 0.42, P(x = 62) P(x = 62) = b. n = 100, p = 0.58, P(53 ≤ x ≤ 59) P(53 ≤ x ≤ 59) = c. n = 90, p = 0.42, P(x ≥ 37) P(x ≥ 37) = d. n = 108, p = 0.77, P(x ≤ 77) P(x ≤ 77) =

Name: find to 4 decimal places the following binomial probabilities using the normal approximation a n 140 p 042 px 62 px 62 b n 100 p 058 p53 x 59 p53 x 59 c n 90 p 042 px 37 px 37 d n 108 p 077 20265
Uploaded: 2023-05-24T11:18:09-08:00
Duration: 1 min 28 s
Channel: Adi S
Description: find to 4 decimal places the following binomial probabilities using the normal approximation a n 140 p 042 px 62 px 62 b n 100 p 058 p53 x 59 p53 x 59 c n 90 p 042 px 37 px 37 d n 108 p 077 20265

          Find to 4 decimal places the following binomial probabilities
using the normal approximation.
a. n =
140, p = 0.42, P(x =
62)
P(x = 62) = 
b. n =
100, p = 0.58, P(53
≤ x ≤ 59)
P(53 ≤ x ≤ 59) = 
c. n =
90, p = 0.42, P(x ≥
37)
P(x ≥ 37) = 
d. n =
108, p = 0.77, P(x ≤
77)
P(x ≤ 77) =

Added by Alex V.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Adi S

05/24/2023

Step 1

Mean (μ) = n * p Standard deviation (σ) = √(n * p * (1-p)) a. n = 140, p = 0.42 μ = 140 * 0.42 = 58.8 σ = √(140 * 0.42 * 0.58) = 7.434 b. n = 100, p = 0.58 μ = 100 * 0.58 = 58 σ = √(100 * 0.58 * 0.42) = 4.949 c. n = 90, p = 0.42 μ = 90 * 0.42 = 37.8 σ = √(90 * Show more…

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Find to 4 decimal places the following binomial probabilities using the normal approximation. a. n = 140, p = 0.42, P(x = 62) P(x = 62) = b. n = 100, p = 0.58, P(53 ≤ x ≤ 59) P(53 ≤ x ≤ 59) = c. n = 90, p = 0.42, P(x ≥ 37) P(x ≥ 37) = d. n = 108, p = 0.77, P(x ≤ 77) P(x ≤ 77) =