Question

First law of thermodynamics: In an isochoric process, the internal (thermal) energy of an ideal gas decreases by 50 J. How much work does the gas do during this process? A) 50J B) 25J C) 0.00J D) -50 J E) -25J

Name: first law of thermodynamics in an isochoric process the internal thermal energy of an ideal gas decreases by 50 j how much work does the gas do during this process a 50j b 25j c 000j d 50 j 98956
Uploaded: 2023-07-07T20:34:33-08:00
Duration: 1 min 3 s
Channel: Adi S
Description: first law of thermodynamics in an isochoric process the internal thermal energy of an ideal gas decreases by 50 j how much work does the gas do during this process a 50j b 25j c 000j d 50 j 98956

          First law of thermodynamics: In an isochoric process, the internal (thermal) energy of an ideal gas decreases by 50 J. How much work does the gas do during this process?
A) 50J
B) 25J
C) 0.00J
D) -50 J
E) -25J

first law of thermodynamics in an isochoric process the internal thermal energy of an ideal gas decreases by 50 j how much work does the gas do during this process a 50j b 25j c 000j d 50 j 98956

Added by Sarah S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

07/07/2023

Step 1

Step 1: The first law of thermodynamics states that the change in internal energy ($\Delta U$) of a system is equal to the heat added to the system ($Q$) minus the work done by the system ($W$): $\Delta U = Q - W$ Show more…

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First law of thermodynamics: In an isochoric process, the internal (thermal) energy of an ideal gas decreases by 50 J. How much work does the gas do during this process? A) 50J B) 25J C) 0.00J D) -50 J E) -25J