00:01
We're supposed to determine the currents using mesh analysis.
00:03
We put in loop currents, and then we use the voltage law to get two loops.
00:39
And then the second one, okay? and then i'm going to simplify those.
02:04
And here's how i'll solve them.
02:06
I'll take that second equation, solve it for i -1, then substitute it back into the first one.
03:23
So there's our currents.
03:24
The one in the 5 -oom resistor is i -1.
03:32
That's one of the answers we want.
03:35
We want that voltage up here so we can use the middle line.
03:55
So we go, that lands us at the ground, so it puts it in zero.
05:37
So we draw the mesh currents here.
05:45
When we draw the mesh currents, it's important that every component has a current.
05:52
The wire down here at the bottom doesn't really matter for calculating the loop laws...