The spring is placed between the wall and the 10-kg block. If the block is subjected to a force of F = 500 N, determine its velocity when s = 0.5 m. When s = 0, the block is at rest and the spring is uncompressed. The contact surface is smooth.
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First, we need to find the spring constant k. We are given that the spring force is 500 N when the block is subjected to a force of F1 = 500 N. Since the block is in equilibrium at this point, the spring force must be equal to the applied force. Therefore, k = 500 Show more…
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A spring of stiffness k = 500 N/m is mounted against the 10-kg block. If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and the spring is uncompressed. (The contact surface is smooth) Solve the problem using the equation of motion (f=ma)
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