An airplane undergoes the following displacements: First, it flies 66 km in a direction 30° east of north. Next, it flies 49 km due south. Using vector components, determine how far the airplane ends up from its starting point.
Added by Joseph M.
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We can use the following equations: $x_1 = r_1 \cos(\theta_1)$ $y_1 = r_1 \sin(\theta_1)$ where $r_1 = 66$ km, and $\theta_1 = 308° - 270° = 38°$ (since we need the angle from the east direction). Now, we can find the components of the second displacement (49 Show more…
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