00:01
Hi, i'm david and i'm here to help you answer your question.
00:04
Now let me bring up your question here.
00:07
In the question here we are going to discuss about the linear question.
00:11
Here we are given the output from the linear recursion of the y equal to the a plus bx and we're given the output for the r square and we will have the output for the intercept and the slop here.
00:29
And the first question a1 here, i'm going to still write down the fitted model.
00:36
So the fitted model will be the y -heart equal to a plus b, x, where we have the value of the a here.
00:45
It will be the intercept and this will be the value of the a.
00:48
And the value of the b will be this will be the slot on the x, b.
00:54
Therefore we have the 0 .519 minus the 0.
01:00
0 .707 times under x and that's going to be the answer for the number one.
01:06
Now for the number two we will need to make the prediction using the fitted model for y when x x to the 1 .888.
01:15
So when x equal to the 1 .888 then we have the y heart equal to we put the value here into the x and then we have the 0 .519 minus 0 .707 times when the 1 .8 equal 2...