For 589-nm light, calculate the critical angle for the following materials surrounded by air. (a) diamond (n = 2.419) (b) crown glass (n = 1.52) (c) ice (n = 1.309)
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For 589 -nm light, calculate the critical angle for the following materials surrounded by air: (a) diamond, (b) flint glass, and (c) ice.
For 589 -nm light, calculate the critical angle for the following materials surrounded by air. (a) diamond (b) flint glass (c) ice
The refractive index of diamond is $2.42 .$ What is the critical angle for light passing from diamond to air? We use $n_{i} \sin \theta_{i}=n_{t} \sin \theta_{t}$ to obtain $$ (2.42) \sin \theta_{c}=(1) \sin 90^{\circ} $$ from which it follows that $\sin \theta_{c}=0.413$ and $\theta_{c}=24.4^{\circ}$.
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