Question

For a 160 km long three-phase transmission line, the unit series impedance of the line is given as (0.125 + j0.53) Ω/km and the parallel (shunt) admittance as 3.75 x 10^-6 S/km. This transmission line feeds a 60 MW load with a lagging power factor of 0.85. Assuming an end-of-line voltage of 110 kV, find the current, voltage, and power values at the beginning of the line.

Name: for a 160 km long three phase transmission line the unit series impedance of the line is given as 0125 j053 km and the parallel shunt admittance as 375 x 10 6 skm this transmission line feed 78865
Uploaded: 2023-08-10T16:22:29-08:00
Duration: 1 min 12 s
Channel: Adi S
Description: for a 160 km long three phase transmission line the unit series impedance of the line is given as 0125 j053 km and the parallel shunt admittance as 375 x 10 6 skm this transmission line feed 78865

          For a 160 km long three-phase transmission line, the unit series impedance of the line is given as (0.125 + j0.53) Ω/km and the parallel (shunt) admittance as 3.75 x 10^-6 S/km. This transmission line feeds a 60 MW load with a lagging power factor of 0.85. Assuming an end-of-line voltage of 110 kV, find the current, voltage, and power values at the beginning of the line.

Added by Wendy R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

08/10/2023

Step 1

The total impedance of the transmission line can be calculated by multiplying the unit series impedance by the length of the line. Given that the unit series impedance is (0.125 + j0.53) Ω/km and the length of the line is 160 km, the total impedance is: Total Show more…

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For a 160 km long three-phase transmission line, the unit series impedance of the line is given as (0.125 + j0.53) Ω/km and the parallel (shunt) admittance as 3.75 x 10^-6 S/km. This transmission line feeds a 60 MW load with a lagging power factor of 0.85. Assuming an end-of-line voltage of 110 kV, find the current, voltage, and power values at the beginning of the line.