For a binomial probability distribution with P = 0.7 and n = 18, find the probability that the number of successes is equal to 12 and the probability that the number of successes is fewer than 6.
Added by Vicenta B.
Step 1
Plugging in the values we have: P(X = 12) = (18 choose 12) * 0.7^12 * 0.3^6 Using a calculator or software, we can find that: P(X = 12) ≈ 0.176 So the probability that the number of successes is equal to 12 is approximately 0.176. Show more…
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