For a certain chemical reaction, the standard Gibbs free energy of reaction at 20.0 °C is -75.9 kJ. Calculate the equilibrium constant K for this reaction. Round your answer to 2 significant digits.
Added by Juan Carlos H.
Step 1
ΔG° = -RT ln K where ΔG° is the standard Gibbs free energy of reaction, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin, and K is the equilibrium constant. Show more…
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