For a chi-square goodness-of-fit test based on a 4x4 contingency table, the test statistic is 19.4218. What is the approximate p-value of the test? Answer:
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Given that we have a 4x4 contingency table, the degrees of freedom is calculated as (number of rows - 1) * (number of columns - 1) = (4-1) * (4-1) = 3 * 3 = 9. Show more…
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