For a confidence level of 98 find the critical z value using...

For a confidence level of 98%, find the critical Z-value using the Standard normal Table. q2. For a confidence level of 92%, find the critical Z-value using the Standard normal Table. q3. You measure 33 watermelons' weights, and find they have a mean weight of 51 ounces. Assume the population standard deviation is 6.9 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean watermelon weight. Give your answer as a decimal, to two places ______ ounces q4. You measure 35 textbooks' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 2.3 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places _______ < μ < _________

Transcript

00:01 Hi, i'm david and i'm here to help you answer your question.

00:03 Now let me pick up your question here.

00:06 In the question here we are going to discuss about the critical value in the competence interval.

00:14 In it to answer this question, i need to put up the z table.

00:17 Let me copy the z table and put the table on the right here.

00:23 In the table here we have the negative g score with the probability on the left tail.

00:29 Now in the first question 1, we want to find the z critical z value for the 98 % complete interval.

00:38 So this value equal to the z on the alpha over 2 and the alpha and the 95 % equal to the 2 % the vain 2 % which is equal to the 0101.

00:50 Now to find this critical value will look for the 0101 and we see the cluster 1 will be this value and corresponds to the z score of the minus 2 .33.

01:02 But we turn the positive value only, therefore we turn the 2 .33.

01:08 That's going to be answered for the number 1.

01:10 For the number 2, instead of the 98, we have the 92, therefore we have the z on the 4 over 2.

01:17 And 5 in this case equal to the 8%, divided by 2 equal to the 4%, which is equal to the z104.

01:24 It will look for the z1 04 inside the table.

01:27 The closest song will be this value, which is corresponds to the minus 1%,000 ,000 ,000 ,000 ,000 ,000.

01:32 Point 75.

01:34 Therefore the value here will be 1 .75.

01:37 Now for the question 3, once you find the matching of the error, we don't know margin of the error by the formula equal to the z and 4 over 2 10 when the sigma over square the n.

01:52 Now we have in this question at the 90 % confidence and 5 % divided by 2 equal to the 5 % which is equal to the z of 0 .0 5.

02:03 And the sigma in this question here it will equal to the 6 .9 over the square of n equal to the 33.

02:13 And then we will have the z under 0 .05 if we look at the table here, we see that will be the average of the two values here, which is if it will be the average of the minus 1 .6 and the average of the 4 and 5.

02:29 Therefore the z number 0 .05 equal to the 1 .6.

02:35 Times under 6 .9 divided by square under 33...

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