00:01
So this is a mixing problem.
00:04
We want to calculate the nitrite iron, the concentration of nitric iron after mixing.
00:14
So the first thing is we know you have the nitric acid.
00:20
And the volume is 35 milliliter.
00:26
And the concentration here is about 0 .255 more.
00:35
And then you have the magnesium nitrate.
00:38
The volume is 45, the concentration is 0 .328 more.
00:53
We want to know after mixing what is the concentration of the nl3.
01:00
So what we can do first is to calculate the most of the nitrate irons.
01:09
It equals to what? it equals to the mores of the nitric iron in the solution 1.
01:17
Plus the mores of the nitric iron in the solution two.
01:24
We can calculate one by one.
01:27
So for the solution one, the mores of nitric iron equals to the most of the nitric acid, equals to the c1 times b1.
01:43
So basically it's 2 .255 times 35 over 1 ,000...