For a macroscopic object of mass 1.0 g moving with speed 1.0 cm/s in a one-dimensional box of length 1.0 cm, find the quantum number n.
Added by Consuelo S.
Step 1
0 \, \text{g} = 1.0 \times 10^{-3} \, \text{kg} \) - Speed of the object, \( v = 1.0 \, \text{cm/s} = 1.0 \times 10^{-2} \, \text{m/s} \) - Length of the box, \( L = 1.0 \, \text{cm} = 1.0 \times 10^{-2} \, \text{m} \) Show more…
Show all steps
Close
Your feedback will help us improve your experience
Sam Stansfield and 95 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A mass of $10^{-6} \mathrm{~g}$ is moving with a speed of about $10^{-1} \mathrm{~cm} / \mathrm{s}$ in a box of length $1 \mathrm{~cm} .$ Treating this as a one-dimensional infinite square well, calculate the approximate value of the quantum number $n$.
Calculate the quantum number (n) for a Ne atom in a one-dimensional box with an energy (E) of 6.25 x 10-21J and a length of 1.00 x 10-8m
Adi S.
A marble of mass $10 \mathrm{g}$ is confined to a box $10 \mathrm{cm}$ long and moves at a speed of $2 \mathrm{cm} / \mathrm{s} .$ (a) What is the marble's quantum number $n ?$ (b) Why can we not observe the quantization of the marble's energy? [Hint: Calculate the energy difference between states $n$ and $n+1 .$ How much does the marble's speed change?]
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD