For a normal distribution with a mean of µ = 500 and a standard deviation of σ = 25, find each of the following probabilities: (a) p(X < 512) (b) p(515 < X < 530)
Added by Timothy C.
Step 1
(a) For X = 512, the z-score is: z = (X - µ) / σ = (512 - 500) / 25 = 12 / 25 = 0.48 (b) For X = 515 and X = 530, the z-scores are: z1 = (515 - 500) / 25 = 15 / 25 = 0.6 z2 = (530 - 500) / 25 = 30 / 25 = 1.2 Now, we can find the probabilities using the standard Show more…
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