00:01
Well, for this question, we need to use a principle of standard normal.
00:08
You need to use a standard normal distribution.
00:13
So we know for standard normal distribution, it's new, is zero, and the standard deviation at sigma is 1.
00:27
And for the question 1, we need to find for the first question we have question a need to find the probability of z less than 2.
00:46
And we can get this value by using a z table, so we can get .9702.
01:02
And for the question b, we need to find a probability is z less than 0 .16.
01:16
And it's equal to 1 minus probability of z less than 1 .16.
01:30
It's equal to 1 minus 0 .877.
01:39
So answer will be 0 .1230.
01:47
And for the question c, we need to find the probability of z between negative 2 .31 and the 2 .31.
02:15
So from the normal distribution diagram, it's kind of this graph, 2 .31, 2 .31.
02:30
Then we need to find this area, right? then we know it's a dynamic.
02:36
This diagram is a dynamic.
02:39
So this two area, red area is a dynamic.
02:45
So our idea is we can use 1 minus the power of 2 times probability of z less than negative 2 .3 1 then we can get this answer so it will be 1 minus 2 times 0104 so the answer will be 1 minus 2 times 0104 so the answer will be go to 0 .9792.
03:31
And for the question d, we need to find that the probability is z less than 1 .82.
03:44
And based on the table, we know its answer is 0 .9656...