Question

For a particular process that is carried out at constant pressure, q = 145 kJ and w = -35 kJ. Therefore, Group of answer choices ΔE = 180 kJ and ΔH = 145 kJ. ΔE = 145 kJ and ΔH = 180 kJ. ΔE = 145 kJ and ΔH = 110 kJ. ΔE = 110 kJ and ΔH = 145 kJ.

Name: for a particular process that is carried out at constant pressure q 145 kj and w 35 kj therefore group of answer choices e 180 kj and h 145 kj e 145 kj and h 180 kj e 145 kj and h 110 kj e 1 11413
Uploaded: 2023-09-04T01:36:08-08:00
Duration: 1 min 3 s
Channel: David Collins
Description: for a particular process that is carried out at constant pressure q 145 kj and w 35 kj therefore group of answer choices e 180 kj and h 145 kj e 145 kj and h 180 kj e 145 kj and h 110 kj e 1 11413

          For a particular process that is carried out at constant pressure, q = 145 kJ and w = -35 kJ. Therefore,
Group of answer choices
ΔE = 180 kJ and ΔH = 145 kJ.
ΔE = 145 kJ and ΔH = 180 kJ.
ΔE = 145 kJ and ΔH = 110 kJ.
ΔE = 110 kJ and ΔH = 145 kJ.

Added by Scott M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

09/04/2023

Step 1

The first law of thermodynamics states that: \[ \Delta E = q + w \] Show more…

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For a particular process that is carried out at constant pressure, q = 145 kJ and w = -35 kJ. Therefore, Group of answer choices ΔE = 180 kJ and ΔH = 145 kJ. ΔE = 145 kJ and ΔH = 180 kJ. ΔE = 145 kJ and ΔH = 110 kJ. ΔE = 110 kJ and ΔH = 145 kJ.