For a
$R_1 = 20 \times 50 = 9.09 \Omega$
$R_2 = \frac{50 \times 40}{110} = 18.18 \Omega$
$R_3 = \frac{20 \times 40}{110} = 7.2727 \Omega$
KCL at V
$V - 2.26 + \frac{V}{34.09} + \frac{V}{118.18} = 0$
$4028.756V - 9104.999 + 859.1V + 247.93V = 0$
$4028.756V = 9104.989$
$V = 2.77286V$
$i_0 = \frac{V}{118.18} = \frac{1.77286}{118.18} = 0.015A$
$i_0 = 0.0150013 Amp$
Q 6)
$45 \times 10^{-3} = 0.45 A$
KCL at $V_0$
$\frac{V_0}{100} + \frac{V_0 + 6.25}{5} + I_0 = 45$
$\frac{V_0 + 20V_0 + 225}{25} + I_0 = 45$
$21V_0 + 25I_0 = 45$
$I_0 = \frac{45 - V_0}{25}$
$22V_0 + 25 \times \frac{45 - V_0}{25} = 45$
$21V_0 + 45 - V_0 = 45$
$22V_0 = 45 - 45$
$V_0 = 0V$