00:01
Hi, i'm david and i'm hedg.
00:02
Have you answered your question? in the question here we are going to discuss about the portion distribution.
00:07
Let me remind you that even the x followed by the possum with the mean equal to the lambda and then the probability of the x equal to the k, equal to the e to the bound minus lambda, lambda power k over k factorial.
00:26
In the question here, if we call the x equal to the number of the earth, earthquakes per year and then we see that the x here will follow by the poso.
00:46
When the mean equal to the lambda and equal two.
00:51
Now to find this one, notice that for the period of the 100 years, then we will have the total of the 107 and 7 earthquake.
01:09
And then now if we just talk about the one year and then the number of the earthquakes, every each equal to 107 divided by 100 equal to 107, 1 .07, 1 .07, earthquake per year.
01:30
So therefore the lambda we're looking for equal to the 1 .07.
01:35
And in the question a, ask let you find the mean.
01:41
So the mean to equal to the lambda and just equals 1 .07 and then earthquake per year.
01:54
And for the question b, we need to find the table on the probability for the x, that it will take the value of the 0, 1, 2, 3, 4, 5, and the last one will be 6 or more.
02:18
And this will be the probability of the x.
02:20
Now if we apply this formula here, with the lambda equal 1 .07.
02:26
And then we go see the first one e to the power minus 1 .007 power 0 over 0 factorial then we get the answer equal to 1 .07 and then get the answer equal to here i need to round the answer to the four decimal places and then we get the answer equal to the 0 .3 430 places and then we get the answer equal to the 0 .3 430 and and from the x .2, 1 .0 .1, we have e to the power minus 1 .07, 1 .07 power 1, over 1, fatale.
03:14
And if we compute it, we get the answer equal to the 0 .367.
03:29
For the x .2, we have e to the bar minus 1 .07, 1 .07 power 2, over 2, over 2, 4 07 ,000, 07 power 2, over 2, 4 2 ,000 for tile...