for a reversible system, the entropy change of the system is equal to entropy transferred with
Added by Gary K.
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In thermodynamics, a reversible process is one that can be reversed without leaving any change in the system and its surroundings. Show more…
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Which of these correctly represents the entropy (s) of an isolated system during a process?
When a system is adiabatic, what can be said about the entropy change of the substance in the system?
The entropy change depends on the initial and final state only so can be calculated for any process whatsoever. We choose to evaluate the entropy change along the pair of lines shown above. Then $\Delta S=\int_{T_{0}} \frac{v C_{V} d T}{T}+\int_{\frac{T_{0}}{\beta}}^{\frac{T_{0}}{\beta}} v C_{p} \frac{d T}{T}$ $=\left(-C_{V} \ln \beta+C_{p} \ln \alpha\right) v=\frac{v R}{\gamma-1}(\gamma \ln \alpha-\ln \beta) \approx-11 \frac{\text { Joule }}{{ }^{\circ} \mathrm{K}}$
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