00:01
Hi students in this question, a unity feedback system is been given whose open loop function is taken as g of s to be equal to 90 into s plus 3 divided by a value of s square into s plus 8 into s plus 6.
00:18
Let this be equation number 1.
00:20
And in the first part of the question we are asked to find out the value of position error constant which is taken as kp.
00:26
And the equation of this kp is taken as kp to be equal to limit s tends to 0 the value of g of s.
00:36
Now by substituting the values, our equation changes as kp to be equal to limit s tends to 0, a value of 90 into s plus 3 divided by s square into s plus 8 into s plus 6, which on simplification gives the value of position error constant, p to be equal to a value of infinity.
00:59
Now in the second part of the question, we are asked to find out the value of velocity error constant which is taken as kv and the equation of kv is taken as kv to be equal to limit s tends to zero the value of s into g of s.
01:15
Now by substituting the equation we get kv to be equal to limit s tends to zero s into 90 into s plus three divided by s square into s plus 8 into s plus 6...