00:01
Hi students in this question, a unity feedback system is been given and its open loop function is taken as g of s to be equal to 50 into s plus 9 the whole divided by s square into s plus 8 into s plus 6.
00:17
Let this be equation number 1.
00:19
And in the first part of the question we are asked to find out the position error constant which is taken as kp.
00:25
And the equation of kp is taken as kp to be equal to limit s tens to 0 the value of g of s.
00:34
And here by substituting the value, we get kp to be equal to limit s 10 to 0, a value of 50 into s plus 9 divided by s square into s plus 8 into s plus 6.
00:49
Which on simplification gives the value of position error constant kp to be equal to a value of.
00:55
Of infinity.
00:56
Now in the second part of the question, we are asked to find out the value of velocity error constant which is taken as kv and the equation of kv is taken as kv to be equal to limit s tends to 0 s into g of s.
01:11
Now by substituting the values our equation changes as kv to be equal to limit s tends to 0 s into a value of 50 into s plus 9 divided by s square into s plus 8 into s plus 6, which on simplification gives the value of kv to be equal to a value of infinity...