00:01
Hello students, here in this session we have given this reaction.
00:03
So we have to add another part of this.
00:06
So we took, we take that zn on oxidation gives zn plus 2 plus 2 electrons.
00:21
So when we combine, combine the reaction then we will get zn plus 2 mno2 plus 2 h2o will give 2 mnooh whole and znoh whole twice.
00:55
So we can say that here zinc is present in 0, here it is present in plus 2.
01:05
So there is a loss of electron.
01:06
So here oxidation is taken place and here mn is present in plus 4, here it is in plus 3 that means there is a gain of electron and here it is a reduction.
01:27
So we have to write the oxidation half reaction.
01:29
So we have to write reaction that occurring at anode.
01:43
So at anode oxidation is occurred.
01:46
So the half reaction of this part that would be zn is converted into zn 2 plus plus 2 electrons.
02:03
Now in part 2, in second part we have to write the overall reaction...