For an ideal battery, closing the switch in the circuit below does not affect the brightness of bulb A. In reality, bulb A will dim just a little when the switch closes. To see why, assume the 1.5 V battery powering the circuit has internal resistance 0.50 Ģ.
A. Calculate the resistance of a lit bulb if the resistivity of the filament at operating temperature is Ģ = 5.60x10^-8 Ģm, the diameter of the filament is d=0.110 mm, and the length of the filament is 1.018 m (yes, they really are that long!).
B. What is the current flowing through bulbs A and B when the switch is left open?
C. What is the current through bulbs A and B after you close the switch?
D. (Choose one of the response options below and explain your reasoning/show your work) How does the current through bulb A change when the switch is open compared to when the switch is closed if we replace the battery with an ideal battery, i.e., r = 0 Ģ?
a. Increases
b. Decreases
c. Stays the same
d. The current through bulb A is so large that it causes the battery to combust.