00:03
In this question, the so2 emission rate is given which is equal to 22 ,000 pounds per day.
00:20
Then again, the value of the exhaust gas flow rate is also given, which will be taken.
00:34
As 2 .0 million meter per hour.
00:43
Then the value of the temperature is given which is 150 degree fahrenheit converting into kelvin this will be 338 .706 kelvin and the value of the pressure p is given which is one atmosphere.
01:03
First first, we will find the emission rate of the so2 converting into gram mole per day.
01:15
So this will be multiplied by thousand and divided by 64.
01:24
So here we will get n is equal to 343750 gram mole per now we find the volume of so2.
01:42
So as we know that ideal gas equation pv is equal to nrt.
01:50
So here we can find the volume so2, this will be equal to nrt divided by pv...