For any full rank matrix, $A \in \mathbb{R}^{n \times n}$, show that $A + A^T$ is symmetric (but not necessarily positive definite) and $AA^T$ is both symmetric and positive-definite.
Added by Jeffrey D.
Close
Step 1
This means that all the rows and columns are linearly independent. Show more…
Show all steps
Your feedback will help us improve your experience
Nick Johnson and 86 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If $A$ is symmetric positive definite and $C$ is nonsingular, prove that $B=C^{T} A C$ is also symmetric positive definite.
Positive Definite Matrices
Tests for Positive Definiteness
Prove that if C is a symmetric positive definite m x m matrix and A is an m x n matrix of rank n (and so m >= n and the map x |-> Ax is injective), then ATCA is symmetric positive definite.
Madhur L.
Let A and B be two n by n square matrices. If B is symmetric, then the matrix C = ATBA is
Adi S.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD