00:01
In the crystal diffraction experiment, we are given the wavelength lambda as 0 .16 nanometer.
00:07
We are asked to find the value of energy if for part given particle is a photon.
00:14
So, for a part of the quotient, we are going to find the energy e which can be found from the formula hc divided by lambda, h is the planck's constant value and c is the speed applied and they combinedly give the value of 1240 electron volt nanometer.
00:34
So, this is the combined value of hc, it is a constant value divided by lambda value is given here as 0 .16 nanometer.
00:45
Solving this, we get the value as 7750 electron volts.
00:53
Then in b part of the quotient, we are asked to find the energy when the particle is an electron.
00:58
So, first let us find the value of momentum.
01:01
So, momentum p will be equal to h by lambda, substitute the values, h is the planck's constant of 6 .63 multiplied by 10 power minus 34 divided by lambda value is 0 .16 multiplied by 10 power minus 9 meter because it is given in nanometer.
01:20
Solving this, we get the momentum as 4 .14 multiplied by 10 power minus 24...