Question

For each condensation reaction, 1) draw the product in the box and 2) provide a mechanism for its formation. NaOH H?O + H?O 1) LDA, -78°C 2) methyl benzoate 3) CH?CH?Br + CH?OH

          For each condensation reaction, 1) draw the product in the box and 2) provide a mechanism for its formation.
NaOH
H?O
+ H?O
1) LDA, -78°C
2) methyl benzoate
3) CH?CH?Br
+ CH?OH

For each condensation reaction, 1) draw the product in the box and 2) provide a mechanism for its formation.
NaOH
H?O
+ H?O
1) LDA, -78°C
2) methyl benzoate
3) CH?CH?Br
+ CH?OH

Added by Matthew H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

05/29/2022

Step 1

Step 1: The product of the condensation reaction is a cyclic compound formed by the reaction of NaOH, H2O, and LDA at -78°C. Show more…

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For each condensation reaction, 1) draw the product in the box and 2) provide a mechanism for its formation.

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Transcript

0:00 Hello, hi, students.

00:01 Let me explain you the question here.

00:03 Here, for the condensation reaction, here they have given condensation reaction.

00:09 For this condensation reaction, we have to draw the product.

00:13 So we have to draw the product and the mechanism of action for this particular reaction.

00:20 So this is the condensation reaction.

00:22 Here the condensation reaction, it is intramolecular condensation reaction, that is intramolecular aldol condensation reaction so what is the intramolecular aldol condensation intra means within within the molecule within the molecule condensation reaction takes place so old refers to aldehyde old refers to alcohol in aldol condensation reaction what happens in intramolecular aldol condensation reaction, the aldehyde groups, that means here, the condensation of condensation of two aldehyde groups or ketone groups in the same molecule, two aldehyde or ketone groups in the same molecule, creetone groups in the same molecule.

01:24 That why same molecule within the molecule condensation takes place.

01:29 So it is known as aldol condensation.

01:32 So here, the product, here we have to predict the product.

01:37 So what is the product here? that is, this is the product.

01:45 Here double bond rule.

01:48 So coming to the mechanism of action, this is the mechanism of action of the particular intermolecular aldol condensation reaction.

01:56 So this is the reactant.

01:58 So this is the reactant.

02:00 So whenever in the presence of aldol condensation takes place in the present, of base that is n -a -o -h.

02:06 Here, as it is strong base, it dissociate into n -a plus o -h -minus.

02:12 Here, oh -h -minus ion will go and interact with the h.

02:16 So it leads to the...

02:17 So this h will be removed of...

02:20 And here, this bond, this particular bond, it will be shifted to here to form the negative charge.

02:27 So, this negative charge, it will go and interact in the presence of water.

02:34 So here water.

02:36 So this particular o minus, it go and interact with the h plus ions of the water.

02:44 So as it interacts with the h plus ions, it forms the hydroxyl group...

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