For each ligand below, give the following information: I....

For each ligand below, give the following information: I. The commonly used abbreviation II. The denticity III. Draw the ligand; use a star to indicate which atom(s) will form bonds with metals (these are referred to as 'donor atoms') IV. Classify the donor atom(s) of the ligand as X- or L-type a. tetrahydrofuran b. o-phenanthroline c. Pyridine d. Cyano e. Carbonyl f. Borohydride g. Acetylacetonate (hint: this is an LX-type ligand, due to the anionic charge) h. bis-(trimethylsilyl)amide i. Ethylenediamine j. Triethylphosphine k. tris(2-pyridylmethyl)amine

Transcript

00:01 Hello student.

00:02 So among the following ligands we have to find out which we have to classify and give the information.

00:12 Information like that is commonly used abbreviation for those ligands and what are its denticity there and which ligand is used.

00:26 Means we have to draw that the structure of that ligand and make the star mark to represent the donor atom here.

00:36 And we have to tell also what kind of donor atom it is.

00:40 It is a x type or it is a l type donor atom.

00:44 So first we have tetrahidrofurin.

00:54 So for tetrahidrofuran, we have.

00:58 The abbreviation that we are using that is thf and the denticity.

01:04 So let us see the first diagram for this.

01:08 We have this pentane ring and oxygen is there.

01:13 And this is the donor atom.

01:17 This is a ligin which will form bond with the metals.

01:21 So the denticity here it is one because here it is a monodentate.

01:27 And it is the l type donor atom.

01:32 See, x type means that which donate or accept only one electron.

01:38 It donate one electron to metal and except one electron from the metal.

01:44 While the l type which donate to two electrons or more electrons, for example, it can be a lone pair or pi electrons can be there, sigma electrons can be there.

01:56 So this is the l type donor atoms.

02:01 So in this case, this tetrahydroferon is l type.

02:06 Now the next one we have orthophenthrolin.

02:14 We have this one.

02:19 So now for the orthophenathophenopin, we abbreviation we use that fin like this.

02:28 And denticity here it is two.

02:31 We can see the structure here that one benjin ring is present there and another benjin ring it is present and one more benjin ring is there this is your phenophthalene and one nitrogen group and one nitrogen group it is present here so you can see there that bi dentate is there therefore the denticity is dual and these two nitrogen atoms are the donor atoms which form the which will form the bond with metal.

03:03 So this is again a l type which can donate because nitrogen contains the lone pair electrons as in case of the oxygen.

03:12 So this is the l type donor atom.

03:18 Next we are given here that is pyridine.

03:23 So pyridine we have abbreviation is py and density in this case it is one and let us draw the structure this is your pyridine and this nitrogen atom is your the donor donor one which will form the bond and again this nitrogen is there loan pair will be there that means two electrons and be donated by this next is the next is we have the sin no group the signo for this we have this abbreviation cn is there and and the denticity is one because it is a monodentate and the structure for this, this like this...

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