00:01
Hello everyone in the question.
00:02
We have alpha is given as 0 decimal 0 5 now for part a we are given data for bsm5 diagnosis male and female.
00:26
So we use we use independent by square.
00:40
So this will be the answer for first part.
00:45
I mean next part the null hypothesis h naught will be there is not associated.
01:07
There is not association between gender.
01:17
I of bsm5 and let alternative alternative hypothesis be given by h1 which is there is an association between genders bsm5 these are the two hypothesis now in next part.
01:58
We have to find test statistics.
02:00
So part c we use by square formula s for this.
02:07
The formula is summation of observed minus expected.
02:15
The whole square divided by expected.
02:23
So from this we have first degree of freedom is given as 2.
02:34
Therefore if we draw the table, we have observed expected and then we have the value observed minus expected whole square divided by expected.
03:00
So the table will be so this will be the required table.
03:06
Now from the table we can find i square is equals to putting the values.
03:11
We will get the value as 22 decimal 4 2 0 6 3...