00:01
Hello students, hope you are doing great.
00:04
In this question we are asked to find out the solubility products of cobalt 2 sulfide and iron 3 back hydroxide.
00:10
We have to find out the solubility products of this given molecules and then compare it with the solubility products of the other given compounds.
00:20
So solubility product of cobalt 2 sulfide can be written as here we have cobalt sulfide which gives cobalt 2 plus iron plus s minus 2 iron.
00:35
Let us consider that the solubility be s for both the ions.
00:39
So the ksp is equals to concentration of co 2 plus iron into concentration of s minus 2 iron.
00:49
So that is equals to s into s.
00:52
So ksp that is the solubility product of cobalt sulfide is equals to s square.
00:57
Next the solubility product of iron 3 hydroxide can be written as here we have fe oh 3 which forms fe plus 3 iron plus 3 oh minus iron.
01:19
The ksp can be written as s into s raised to the power 3 as the stoichiometric coefficient for oh minus is 3 here.
01:32
Therefore ksp is equals to s raised to the power 4.
01:35
Let this be number 2 and solubility product of cobalt sulfide be the number 1.
01:43
The next compound that we are given are ag 3 po 4 which can be written as 3 ag plus plus po 4 3 minus.
01:58
So the ksp for this can be written as s raised to the power 3 as the stoichiometric coefficient here is 3 into s.
02:06
So ksp is equals to s raised to the power 4 for ag 3 po 4...