00:01
In this question for pb i2 solid giving pb2 plus acquiesce plus 2 i .m.
00:21
It is given that k is equal to 1 .4 into 10 raise 2 minus 2 .8 which is at 25.
00:39
Degrees celsius and the standard gibbs energy of formation of pbi2 solid is minus 173 .64 kilojoules per mold.
00:58
We need to calculate the standard gibbs energy of formation of pbi2 acquies.
01:14
We all know that the equation is p b i2 solid giving p b2 plus acquies plus 2 i minus acquies and the k value is 1 .4 into 10 raise to minus 8.
01:40
Given that delta g 0 formation is equal to of p b i 2 is given as minus 173 point 6 4 kilojoude.
01:56
Now reversing this above equation we get pb2 plus aquas plus 2 i minus aquis giving p b i2 solid that is k dash is equal to 1 by k p b i 2 acquies giving p b i 2 solid which is giving k -dash is equal to 1 by k.
02:32
Now the k -dash will be 1 by k, that is 1 by 1 .4 into 10 raise to minus 8, which is obtained as 7 .143 into 10 rise to 7.
02:45
Now we all know that delta g0 reaction of the reaction is equal to minus rt lon k, that is minus 8 .314...