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For problems 9 and 10, complete the alternative hypothesis by circling the correct inequality, find the P-value, and circle the correct words in the statements about the null hypothesis and the claim for the hypothesis test. Use a significance level of 0.05 to test the appropriate hypothesis. 9. The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statistics include n=696 drowning deaths of children, with 209 of them attributable to beaches. Use a significance level of 0.05 to test the appropriate hypothesis. H0: p = 0.25 Ha: p > 0.25 P-value = We (reject / fail to reject) the null hypothesis. There (is / is not) sufficient evidence to (reject / support) the claim. 10. A marketing survey involves product recognition in New York and California. Of 558 New Yorkers surveyed, 193 knew the product while 196 out of 614 Californians knew the product. Test the claim that the recognition rates are the same in both states. H0: p1 = p2 Ha: p1 ≠ p2 P-value = We (reject / fail to reject) the null hypothesis. There (is / is not) sufficient evidence to (reject / support) the claim.

          For problems 9 and 10, complete the alternative hypothesis by
circling the correct inequality, find the P-value, and circle the
correct words in the statements about the null hypothesis and the
claim for the hypothesis test. Use a significance level of 0.05 to
test the appropriate hypothesis.

9. The claim is that the proportion of drowning deaths of
children attributable to beaches is more than 0.25, and the sample
statistics include n=696 drowning deaths of children, with 209 of
them attributable to beaches. Use a significance level of 0.05 to
test the appropriate hypothesis.

H0: p = 0.25 Ha: p > 0.25
P-value = We (reject / fail to reject) the null hypothesis.
There (is / is not) sufficient evidence to (reject / support)
the claim.

10. A marketing survey involves product recognition in New York
and California. Of 558 New Yorkers surveyed, 193 knew the product
while 196 out of 614 Californians knew the product. Test the claim
that the recognition rates are the same in both states.

H0: p1 = p2 Ha: p1 ≠ p2
P-value = We (reject / fail to reject) the null hypothesis.
There (is / is not) sufficient evidence to (reject / support)
the claim.

Show more…

Added by Linda W.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Adi S

07/17/2022

Step 1

25. - Null Hypothesis: \(H_0: p = 0.25\) - Alternative Hypothesis: \(H_a: p > 0.25\) Show more…

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For problems 9 and 10, complete the alternative hypothesis by circling the correct inequality, find the P-value, and circle the correct words in the statements about the null hypothesis and the claim for the hypothesis test. Use a significance level of 0.05 to test the appropriate hypothesis. 9. The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statistics include n=696 drowning deaths of children, with 209 of them attributable to beaches. Use a significance level of 0.05 to test the appropriate hypothesis. H0: p = 0.25 Ha: p > 0.25 P-value = We (reject / fail to reject) the null hypothesis. There (is / is not) sufficient evidence to (reject / support) the claim. 10. A marketing survey involves product recognition in New York and California. Of 558 New Yorkers surveyed, 193 knew the product while 196 out of 614 Californians knew the product. Test the claim that the recognition rates are the same in both states. H0: p1 = p2 Ha: p1 ≠ p2 P-value = We (reject / fail to reject) the null hypothesis. There (is / is not) sufficient evidence to (reject / support) the claim.

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Transcript

00:02 In the ninth problem, the claim given is the proportion of drowning deaths of children attributable to p.

00:09 Chess is more than 0 .25.

00:13 The null hypothesis of the study is p is equal to 0 .25 and alternative hypothesis is p is greater than 0 .25.

00:25 Note that this is a right -tailed test as the direction of alternative hypothesis is greater than.

00:32 From the given information, n is 209 and x is, sorry, x is 209 and n is 696.

00:47 Let us find the sample proportion p had.

00:51 The formula to find the sample proportion is x by n.

00:55 Replacing the values, it can be written as 209 divided by 696, which is approximately equal to 0 .3 -303.

01:09 The test statistic of the test can be obtained using the formula z is equal to b had minus b divided by square root of.

01:21 P into 1 minus b divided by n.

01:24 Replacing the values in the formula, this can be written as 0 .303 minus 0 .25 divided by square root of 0 .25 into 1 minus 0 .25 divided by 696, which is approximately equal to 3 .0638.

01:49 The p value of the test can be obtained using the excel formula is equal to 1 minus norm.

01:59 Dot yes dot test 3 .0638 comma true.

02:07 Thus the excel output obtained is shown below.

02:12 From the excel output the pay value of the test is observed to be 0 .001...

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