00:01
So if we have the native protein undergoing an equilibrium where it produces the denatured protein, and then k is going to be the concentration of the denatured protein, divided by the concentration of the native protein, and that value is, that numerical value, is provided at 2 .58 times 10 to the negative 3.
00:41
K is always the concentration of the product or the concentration of the reactant.
00:49
So if we dissolve 4 .6 times 10 to the negative 6 moles of the protein in 1 milliliter, then we have an initial concentration.
01:01
I move this around a little bit.
01:10
I move this over.
01:14
I have an initial concentration of the native protein of 4 .6 times 10.
01:25
To the negative 6 divided by 1 mill liter which is 0 .001 liters.
01:32
That's my initial concentration.
01:34
What is the molar concentration of the denatured form at equilibrium? well the change will occur.
01:43
Well this will decrease by x.
01:45
The denatured protein will increase by x and at equilibrium i'll have 4 .6 times 10 to the negative 3, i calculated this minus x in x...