Question

For below circuit, reflect the secondary side elements to the primary side. What is the real part of the total impedance at the primary side? $V_s = 120 \angle 0^\circ V$; $R_p = 0.2 \Omega$; $X_p = 0.3 \Omega$; $R_s = 10 \Omega$; $X_s = 20 \Omega$; $Z_L = 200 + j100 \Omega$

          For below circuit, reflect the secondary side elements to the primary side. What is the real part of the total impedance at the primary side?
$V_s = 120 \angle 0^\circ V$; $R_p = 0.2 \Omega$; $X_p = 0.3 \Omega$; $R_s = 10 \Omega$; $X_s = 20 \Omega$; $Z_L = 200 + j100 \Omega$

For below circuit, reflect the secondary side elements to the primary side. What is the real part of the total impedance at the primary side?
Vs = 120 ∠ 0^∘ V; Rp = 0.2 Ω; Xp = 0.3 Ω; Rs = 10 Ω; Xs = 20 Ω; ZL = 200 + j100 Ω

Added by Margarita B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

04/26/2023

Step 1

The reflected resistance at the primary side (Rp') is given by: Rp' = (N^2) * Rs = (10^2) * 10 = 1000 ohms The reflected reactance at the primary side (Xp') is given by: Xp' = (N^2) * Xs = (10^2) * 20 = 2000 ohms Show more…

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For the below circuit, reflect the secondary side elements to the primary side. What is the real part of the total impedance at the primary side? Vs=120 Z0V; Rp=0.2; Xp=0.3; Rs=10; Xs=20; ZL=200+j100 1:10 MM RS iXs