For the chemical reaction Ca (s) + ½ O₂ (g) → CaO (s) ∆H° = -635 kJ/mol. What is the molar enthalpy (in kJ/mol) for the reaction 2 CaO (s) → 2 Ca (s) + O₂ (g)?
Added by Joel W.
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Certainly! To find the molar enthalpy (\(\Delta H^\circ\)) for the reverse reaction \(2 \text{CaO (s)} \rightarrow 2 \text{Ca (s)} + \text{O}_2 \text{(g)}\), we'll follow these steps: ### Show more…
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For the chemical reaction Ca (s) + ½ O₂ (g) → CaO (s) ∆H° = -635 kJ/mol. What is the enthalpy for the reaction 2 CaO (s) → 2 Ca (s) + O₂ (g)?
Adi S.
Using the equations Ca (s) + ½ O₂ (g) → CaO (s) ΔH° = -635 kJ/mol CaO (s) + H₂O (l) → Ca(OH)₂ (s) ΔH° = -64 kJ/mol 2 H₂ (g) + O₂ (g) → 2 H₂O (l) ΔH° = -572 kJ/mol Determine the enthalpy for the reaction Ca (s) + 2 H₂O (l) → Ca(OH)₂ (s) + H₂ (g).
Ashley B.
Using the equations 2 H2 (g) + O2 (g) → 2 H2O (l) ΔH° = -572 kJ/mol Ca (s) + ½ O2 (g) → CaO (s) ΔH° = -635 kJ/mol CaO (s) + H2O (l) → Ca(OH)2 (s) ΔH° = -64 kJ/mol Determine the enthalpy for the reaction Ca (s) + 2 H2O (l) → Ca(OH)2 (s) + H2 (g).
Tianyu L.
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