120 V ?0° 20 nF Vout 12 k?
Added by Darren C.
Close
Step 1
The cutoff frequency for the filter can be calculated using the formula f_c = 1/(2πRC), where R is the resistance and C is the capacitance. Here, R = 12 kΩ = 12,000 Ω and C = 20 nF = 20 x 10^-9 F. So, f_c = 1/(2π * 12,000 * 20 x 10^-9) = 663.12 Hz. b. The Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 76 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Consider an $L C$ circuit with $L=15 \mathrm{mH}$ and $C=2500 \mathrm{pF}$ (Fig $\mathrm{P} 22.42$ ). a. At what frequency is the reactance of the inductor equal to the reactance of the capacitor? b. What is the resonant frequency of this circuit?
Alternating-Current Circuits and Machines
Resonance
What is the resonance frequency of an LC circuit consisting of a 26.0 μF capacitor and a 0.010 H inductor? a 31.0 kHz b 2.0 kHz c 3.1 kHz d 0.31 kHz
Suman K.
An oscillator circuit consists of an inductance of 0.5mH and a capacitor of 20 uF . The resonant frequency of the circuit is nearly (a) 15.92 Hz (b) 159.2 Hz (c) 1592 Hz (d) 15910 Hz
Kamlesh G.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD