00:02
Hello student, here due to virtual ground potential at the inverting terminal is zero.
00:07
So, applying kirchhoff's law in this branch we have zero minus ix into 20 into 10 to the power 3 minus minus of 3 equals to zero.
00:20
So, ix equals to 1 .5 into 10 to the power minus 4 ampere.
00:27
So, ix equals to 1 .5 into 10 to the power minus 4 ampere.
00:40
Now, let's assume the current in the circuit in this circuit is i1 and current in the circuit is i2.
00:51
So, i1 equals to equals to 4 divided by 10 into 10 to the power 3 ampere.
01:05
So, which is equals to 4 into 10 to the power minus 4 ampere and i2 equals to 6 divided by 30 into 10 to the power 3 ampere.
01:20
So, which is equals to 2 into 10 to the power minus 4 ampere...