Question

C_f = 2µF R_2 = 0.5MΩ V_2 V_1 R_1 = 0.75MΩ V_- V_+ +15 -15 V_out

          C_f = 2&#181;F
R_2 = 0.5M&#937;
V_2
V_1
R_1 = 0.75M&#937;
V_-
V_+
+15
-15
V_out

Cf = 2 #181;F
R2 = 0.5M #937;
V2
V1
R1 = 0.75M #937;
V-
V+
+15
-15
Vout

Added by Scott S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

09/06/2023

Step 1

The output voltage (Vout) of a differential amplifier is the difference between the two input voltages (V1 and V2) multiplied by the gain of the amplifier. The gain of the amplifier is determined by the ratio of the feedback resistor (R2) to the input resistor Show more…

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For the circuit shown below, V1 = 10sin(200t) and V2 = 15sin(200t). What is Vout? The op-amp is ideal with infinite gain. Write your answer in the form Vout = Acos(Bt). A = ....................... Write your answer to 2 decimal places B = .............................

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