00:01
Hello everyone in the present problem it is given that the voltage source b is 181 volt coming to the a part of the problem we have a equivalent capacitance c e q 4 micro ferret and 15 micro ferret capacitors are series.
00:47
Therefore, 1 by c is equal to 1 by 4 plus 1 by 50, which is equal to 15 plus 4 divided by 60, which is equal to 19 divided by 60.
01:06
Therefore, c is equal to 60 divided by 19 microferred.
01:14
Now, 60 divided by 19 micro -farrid and 12 micro -farrid are in parallel.
01:35
Therefore, c .e .q is equal to 60 divided by 19 plus 12, which is equal to 15 .15 .1578 micro -farrut.
01:53
Therefore, we have equivalent capacitance c .e .q is equal to 15 .1578 micro -farrid.
02:23
Coming to the b part of the problem, charge stored on.
02:40
50 micro ferret capacitor is q1 is equal to 2.
02:55
C1 multiplied by me.
02:58
Therefore, q1 is equal to 15 multiplied by 181 which is equal to 2 ,715 microcooler.
03:15
2.
03:18
4 micro ferret capacitor q2 is equal to c2p.
03:29
Therefore, q2 is equal to 4 multiplied by 181, which is equal to 724 microcooler.
03:44
3, 12 microferret capacity.
03:56
Q3 is equal to c3p.
04:01
Therefore q3 is equal to 12 multiplied by 181 which is equal to 2 ,172 microcooler.
04:15
Hence we have charge stored on the 15 micro ferret capacitor is 2 ,750 microculeum 4 micro ferret capacitor is 724 microculeum.
05:02
3rd 12 micro ferret capacitor is 2 ,172 microculem.
05:16
C part of the problem voltage.
05:28
Across, first one, 15 microbarred capacitor is p1 equal to q1 divided by c1.
05:48
Therefore, b1 is equal to 2 ,715 divided by 15 which is equal to 181 vote.
06:04
4 .0 micro -farrid capacitor.
06:10
So, here we have v2 is q2 divided by c2...