00:01
Okay, let's see if we can figure this out.
00:02
We're told that the vanadium 3 plus ion forms green salts, and it's a good reducing agent.
00:08
So it's transformed into colorless vo form parentheses 4 with a plus charge vanadic hydroxide ion.
00:22
So the vanadium sulfate can be transferred according to the equation i've written right here.
00:33
And we are asked to give the box oxidation numbers of each of these.
00:38
Okay.
00:45
Oxidation numbers for this one is 3 plus and this one is negative 4 or 5 plus.
01:00
Okay, let me see if that's good for a.
01:01
What is the oxidation on the left? what's the oxidation on the right? now let's do part b.
01:09
B says using that complete and balance the equation.
01:25
Okay, i think we can do that.
01:29
It's not terribly common, but i'm going to slide down a little bit and rewrite this again.
01:35
B2, i'm going to leave the states off for the balancing.
01:55
B2so4 3 voh 4 plus.
02:07
Okay, first order of business.
02:10
I'm going to have to put a 2 right here to get my vanadiums.
02:16
Okay.
02:20
Now let's take care of our h's.
02:27
I'm going to have to add 8 h2os on this side.
02:34
That gives me 12 plus 8, 20.
02:38
And i have 4 times 2.
02:49
How many so4's do i need? so i've got 12 times 8 is 20.
02:53
Okay, so that's good.
02:56
Now h's, i have 16 h's on this side and 8, so i'll need 8 h pluses on this side.
03:06
Okay, now that should be good here.
03:08
The only thing left is electrons.
03:12
And here i have 8 pluses, 6 minuses.
03:19
Let me look again.
03:24
I have 2 pluses right here and 8 pluses right there.
03:27
So i have 10 pluses.
03:29
I have 6 minuses, so i need 4 electrons on this side.
03:37
Okay, so this is looks pretty good to me.
03:42
And you might be able to rewrite my h2so4.
03:55
I might be able to take...
03:58
Oh no, i probably couldn't because i have 4...