For the cross-sectional areas shown, calculate the moment of inertia with respect to the horizontal X-X centroidal axis. (5 points) 28" X 4" 6" 4" X 3" 4" 16"
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Rectangle 1: Width = 28 inches Height = 3 inches Moment of inertia = (1/12) * width * height^3 = (1/12) * 28 * 3^3 = 63 in^4 Rectangle 2: Width = 16 inches Height = 4 inches Moment of inertia = (1/12) * width * height^3 = (1/12) * 16 * 4^3 = 85.33 in^4 Triangle Show more…
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