00:01
This question we have to provide in part a, a point estimate for the average breaking distance of automobiles that makes 3 ,250 pounds.
00:13
In b part, we have to construct the 80 % confidence interval for that mean value.
00:18
And c part, is it valid to make the same estimate for 5 ,000 pound automobiles? we have to explain.
00:25
We have given the data.
00:26
So as per data, if we draw the data in a tabular form, then for x and y, we have the data.
00:48
The value x is 25, y is 105, x is 27 .5, and y is 27 .5, and y is 125, x is 27 .5, and y is 32 .5 and y is 140 140 and for 35.
01:25
And for 35, y is 140.
01:31
And for 45, y is 150.
01:39
So we will design a regression statistics, regression statistics, so regression statistics multiple are equal to 0 .885 r2 square equal to 0 .7805 and adjusted r squared.
02:45
Adjusted r square equal to 0 .7073 standard error equal to 9 .4864 9 .4864 and observations by 0 .00.
03:35
So this is the regression statistic.
03:40
Next we have an over table.
03:48
So on our table we have regression and regressure and residue and total and for these three rows we have column values df degree of freedom regression it is one residual it is three total is four for ss and 269 .9742, 1230 .00, then we have ms, ms is 960 .0258 and 89.
05:28
09914.
05:31
Similarly for f we have the data 10 .68680 and for significance of we have 0 .469.
06:06
Then we have intercept and x...