00:01
So for the first part of this question, it looks like they've already carried out the calculation strategy for you.
00:06
We're just going to focus on k -a -1 in order to solve for the hydronium concentration.
00:12
The hydrogenium concentration is going to be equal to x, and when we solve for x, we get 0 .000 -039 molar.
00:23
But because x being the hydronium concentration based upon the stoichiometry of the reaction is also equal to h a minus so when we go to the next reaction h a minus creating a little bit more h plus plus a 2 minus where they say that this initially is x x and zero and then y is minus x, oops minus, sorry, the change is minus y plus y and y.
01:09
K -a -2 will be equal to the h -plus concentration, which is x, multiplied by the a2 -minus concentration, which is y, divided by the h -a -minus concentration, which is x.
01:26
So, if we assume that y is small with respect to x, then the ha concentration, h .a...