For the equilibrium below at 400 K, Kc = 7.0. Br2(g) + Cl2(g) 2 BrCl(g) If 0.30 mol of Br2 and 0.30 mol Cl2 are introduced into a 1.0 L container at 400. K, what will be the equilibrium concentration of BrCl?
Added by Brian B.
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Write the expression for Kc: Kc = [BrCl]^2 / ([Br2] * [Cl2]) Show more…
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For the equilibrium below at 400 K, Kc = 7.0. Br2(g) + Cl2(g) 2 BrCl(g) If 0.25 mol of Br2 and 0.25 mol Cl2 are introduced into a 1.0 L container at 400. K, what will be the equilibrium concentration of BrCl? M
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