Question

For the following exercise, given the function $f$, evaluate $f(-3)$, $f(-2)$, $f(-1)$, and $f(0)$.\\ $f(x) = \begin{cases} -3x^2 + 4 & \text{for } x < -2\\ 5x - 6 & \text{for } x \ge -2 \end{cases}$\\ f(-3) = -20\\f(-2) = \\f(-1) = \\f(0) =

          For the following exercise, given the function $f$, evaluate $f(-3)$, $f(-2)$, $f(-1)$, and $f(0)$.\\
$f(x) = \begin{cases} -3x^2 + 4 & \text{for } x < -2\\ 5x - 6 & \text{for } x \ge -2 \end{cases}$\\
f(-3) = -20\\f(-2) = \\f(-1) = \\f(0) =

For the following exercise, given the function f, evaluate f(-3), f(-2), f(-1), and f(0).

f(x) = -3x^2 + 4 for x < -2
5x - 6 for x ≥ -2

f(-3) = -20
f(-2) =
f(-1) =
f(0) =

Added by Juan B.

Precalculus with Limits

Ron Larson 2nd Edition

Thanks for your feedback!

For the following exercise, given the function f, evaluate f(-3),f(-2),f(-1), and f(0). f(x)={(-3x^(2)+4 for x<-2):} 5x-6 for x>=-2 f(-3)= f(-2)= f(-1)= f(0)= For the following exercise, given the function f, evaluate f (-3), f (--2), f (-1), and f (0) -3x2+4forx<-2 15-6 for x -2 f(x)= f (-3)= -20 X f (2)= f (-1)= f (0) =