00:01
So probability distribution of a discrete random variable x is given as follow.
00:05
This is the random variable x and this is the probability of each random variable x.
00:12
Now first we need to find the expected value of x.
00:16
So expected value of x is given by some expected value of x is given by summation.
00:22
I goes from 0 to 10 xi into p of xi.
00:29
I goes from 0 to an in summation i goes from 0 to and x i into p of x i that is we need to multiply each term with their probability so this is equal to it would be 0 into 0 .1 that is 0 plus 1 into 0 .2 that is 0 .02 then 2 into then 2 then 2 into 0 .1 2 into 0 .1 it will be 0 .2 plus 0 .3 3 into 0 .2, 0 .06 plus 0 .6 plus 0 .6 plus 0 .6 plus 7 into 0 .08 would be 0 .56 plus 8 into 0 .09 would be 0 .72 .72.
01:23
And then plus 9 into 5 would be 0 .45 plus 8 would be 0 .9.
01:30
So we need to add this term and by adding this term it comes out to be 5 .25.
01:37
So this implies that expected value of x is equals to 5 .25.
01:43
Expected value of x is equal to 5 .25.
01:46
Now the second thing we need to find the variance of this...