00:01
So to solve for this, that's right.
00:03
First, the balance equation, we have p4, plus chlorine gas to form p, cl3.
00:10
So to balance this, we'll write here, four, and then six here.
00:15
So that's the balance equation.
00:17
Now let us identify first the limiting reactant.
00:19
Let's calculate the number of moles of each reactant, p4.
00:22
If we have 11 .3 grams, convert this to moles by dividing the molar mass of p4, 1 -2 -3 .88 grams per mole.
00:33
Okay, so we could cancel this.
00:35
And then we'll get 0 .091 -2.
00:39
This is moles of the 4.
00:41
And then for chlorine gas, if we have 41 .8 grams of this, convert this to moles by dividing the molar mass of cl2, 70 .9 grams.
00:52
Here we have moles, and we'll get 0 .590.
00:56
This is moles of chlorine gas.
00:58
Now, let's calculate the mole ratio.
01:03
So, mole ratio in this case will be the number of moles of the reactant divided by the coefficient of that reactant from the balance equation.
01:12
So for p4, the coefficient is 1.
01:15
So this will be divided by 1 and we'll still get 0 .091.
01:20
So for chlorine gas, we have 0 .590 divided by the coefficient 6 divided by 6, and we'll get 0 .0 .912.
01:29
0 .093...