Question

For the following reaction, 25.5 grams of nitrogen monoxide are allowed to react with 1.40 grams of hydrogen gas. nitrogen monoxide (g) + hydrogen (g) nitrogen (g) + water (l) What is the maximum amount of nitrogen gas that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams

Name: for the following reaction 255 grams of nitrogen monoxide are allowed to react with 140 grams of hydrogen gas nitrogen monoxide g hydrogen g nitrogen g water l what is the maximum amount of 44056
Uploaded: 2022-08-09T06:07:35-08:00
Duration: 2 min 36 s
Channel: Ma Ednelyn Lim
Description: for the following reaction 255 grams of nitrogen monoxide are allowed to react with 140 grams of hydrogen gas nitrogen monoxide g hydrogen g nitrogen g water l what is the maximum amount of 44056

          For the following reaction, 25.5 grams
of nitrogen monoxide are allowed to
react with 1.40 grams
of hydrogen gas.
nitrogen monoxide (g)
+ hydrogen (g) nitrogen (g)
+ water (l)
What is the maximum amount of nitrogen
gas that can be formed?  __________ grams
What is the FORMULA for the limiting
reagent? 
What amount of the excess reagent remains after the reaction is
complete? __________  grams

Added by Stephanie W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ma Ednelyn Lim

08/09/2022

Step 1

5 grams Molar mass of NO = 30.01 g/mol Moles of NO = 25.5 g / 30.01 g/mol = 0.637 moles Show more…

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For the following reaction, 25.5 grams of nitrogen monoxide are allowed to react with 1.40 grams of hydrogen gas. nitrogen monoxide (g) + hydrogen (g) nitrogen (g) + water (l) What is the maximum amount of nitrogen gas that can be formed? __________ grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? __________ grams